2b^2-10b+17=0

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Solution for 2b^2-10b+17=0 equation:


Simplifying
2b2 + -10b + 17 = 0

Reorder the terms:
17 + -10b + 2b2 = 0

Solving
17 + -10b + 2b2 = 0

Solving for variable 'b'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
8.5 + -5b + b2 = 0

Move the constant term to the right:

Add '-8.5' to each side of the equation.
8.5 + -5b + -8.5 + b2 = 0 + -8.5

Reorder the terms:
8.5 + -8.5 + -5b + b2 = 0 + -8.5

Combine like terms: 8.5 + -8.5 = 0.0
0.0 + -5b + b2 = 0 + -8.5
-5b + b2 = 0 + -8.5

Combine like terms: 0 + -8.5 = -8.5
-5b + b2 = -8.5

The b term is -5b.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5b + 6.25 + b2 = -8.5 + 6.25

Reorder the terms:
6.25 + -5b + b2 = -8.5 + 6.25

Combine like terms: -8.5 + 6.25 = -2.25
6.25 + -5b + b2 = -2.25

Factor a perfect square on the left side:
(b + -2.5)(b + -2.5) = -2.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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